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H3C Constructing H3C High-Performance Campus Networks Sample Questions (Q301-Q306):

NEW QUESTION # 301
如图所示组网中, RT1 、 RT2 和 RT3 之间运行 PIMSM 协议, RP 为 1.1.1.1RT3 上连有接收者,且在相应接口上使能 IGMP ,组播源 2.2.2.2 连接在 RT2 上在 RT3 査看单播路由表如下:
[RT3]display ip routing-table
Routing Tables: Public
Destinations : 11 Routes : 12
Destination/MaskProtoPreCost NextHop Interface
1.1.1.1/320SPF 10 1562 192.168.0.1 S0/2/0
2.2.2.2/320SPF 10 1562 192.168.2.1 so/2/1
127.0.0.0/8 Direct 00127.0.0.1 InLoopO
127.0.0.1/32Direct 00127.0.0.1 InLoopO
192.168.0.0/30Direct 00192.168.0.2 S0/2/0
192.168.0.1/32Direct 00192.168.0.1 S0/2/0
192.168.0.2/32Direct 00127.0.0.1 InLoopO
192.168.1.0/300SPF 10 3124 192.168.2.1 so/2/1
OSPF 10 3124 192.168.0.1 S0/2/0
192.168.2.0/30Direct 00192.168.2.2 so/2/1
192.168.2.1/32Direct 00192.168.2.1 so/2/1
192.168.2.2/32Direct 00127.0.0.1 InLoopO
那么,当接收者（ Receiver )发送组加入请求后,下列哪些路由器上存在（ * , G )表项

• A. RT1
• B. RT3
• C. RT2

Answer: A,B
NEW QUESTION # 302
客户局域网交换机 SWA 、 SWB 、 SWC 、 SWD 上构成 RRPP 环主环 1 交换机 SWD 与交换机 SWB 、 SWC 相连,与交换机 SWA 不相连。交换机 SWD 上有如下配置信息:
[SWD]rrpp domain 1
[SWD-rrpp-domain 1 ]ring 1 node-mode transit primary-port gigabitethernet 2/0/1 secondary-port gigabitethernet 2/0/2 level 0
如果交换机 SWA 为主环 1 主节点,如果交换机 SWD 端口 GigabitEthem1/0/ 故障,从上述信息可以得知

• A. 交换机 SWA 立即将状态切换到 Failed 状态,放开副端口
• B. 交换机 SWC 立即将状态切换到 Failed 状态,放开副端口
• C. 如果交换机 SWD 发现端口 Gigabit 口重新 Up 后,立即解除该端口的阻塞状态
• D. SWA 将发送 Link-Down 报文通知所有节点

Answer: A
NEW QUESTION # 303
关于 MSTP 的兼容性配置,说法正确的有

• A. 不同厂商交换机进行 MSTP 互通时,只要保证域名、修订级别、 VLAN 实例映射关系配置完全相同,就可以保证交换机属于同一个 MST 域
• B. H3C 交换机可以通过配置摘要侦听,实现和其他厂商交换机的 MSTP 互通,
• C. 由于不同厂商密钥不同,即使 VLAN 实例映射关系相同,也可能得到不同的摘要结果
• D. 配置了摘要侦听时, H3C 交换机在进行摘要计算时,会使用和对端厂商相同的哈希算法和密钥

Answer: B,C
NEW QUESTION # 304
下列关于 PIMSM 中 RP 选择的表述,正确的有

• A. 最后比较 C-RP 地址,值较大者获胜
• B. 为两个不同的组播组一定会选择不同的 RP
• C. 首先比较 C-RP 的优先级,优先级较高者获胜
• D. 再比较 Hash 函数计算的哈希值,值较大者获胜

Answer: A,C,D
NEW QUESTION # 305
如图组网, SWA 和 SWB 启用 STP , SWC 没有启用 STP 初始时链路 2 没有连接, PCB 可以将数据发到 PCA ,如果此时链路 1 故障,维护人员将链路 2 连接,则关于 PCB 到 PCA 数据传送业的恢复过程的说法正确的有（假设 PCA 不会主动发送数据) __

• A. 由于 SWA 链路中断会引发拓扑改变处理过程,使得 SWA 和 SWB 的 MAC 地址老化时间缩短,所以业务恢复默认需要 15 秒时间
• B. 由于 SWB 的端口 E0/1 默认需要 30 秒的时间进入转发状态,所以业务需要默认 30 秒的时间才能恢复
• C. 业务恢复需要等待 SWC 的 MAC 地址老化,所以需要默认 300 秒的时间
• D. 当 SWB 的端口 E0/1 进入 Forwarding 状态会引发拓扑改变处理过程,所以业务最终恢复需要默认 30+15=45 秒的时间

Answer: C
NEW QUESTION # 306
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